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Mathematics 14 Online
OpenStudy (anonymous):

rearrange your equation to isolate a:(a+b/c)(d-e)=f

zepdrix (zepdrix):

Is it suppose to look like this? \[\large \left(\color{orangered}{\frac{a+b}{c}}\right)\left(d-e\right)=f\] Or like this? \[\large \left(\color{orangered}{a+\frac{b}{c}}\right)\left(d-e\right)=f\]

zepdrix (zepdrix):

If the pretty math pictures didn't show up, let me know.

OpenStudy (anonymous):

the second one

zepdrix (zepdrix):

Hmm darn, that makes things a little trickier.

zepdrix (zepdrix):

We'll start by expanding out the brackets. Remember how to multiply those out? `FOIL` them out, or whatever it's called :)

OpenStudy (anonymous):

so multiply the f by everything

zepdrix (zepdrix):

Oh woops, we don't need to multiply the brackets out, my mistake.

zepdrix (zepdrix):

Let's start by dividing both sides by \((d-e)\).

OpenStudy (anonymous):

ok so it would look like this? a+b/c=f/d-e?

zepdrix (zepdrix):

Yes good c:

OpenStudy (anonymous):

haha ok. so now would we divide b/c on both sides?

zepdrix (zepdrix):

No, next we want to subtract \(\dfrac{b}{c}\) from each side \:D/

zepdrix (zepdrix):

If you divided, you would also have to divide a by b/c, which would create a big mess.

OpenStudy (anonymous):

Haha! sorry! so when we subtract it would leave us with f/d-e-b/c? sorry i dont know how to do the equation thing

zepdrix (zepdrix):

Yes. \[\large a+\frac{b}{c}=\frac{f}{d-e}\] Will become,\[\large a=\frac{f}{d-e}-\frac{b}{c}\]

zepdrix (zepdrix):

You could prolly combine fractions or whatever. But I don't think that's necessary. I think they just want you to stop here, now that we've solved for a.

OpenStudy (anonymous):

Thank you so Much you really did help me. How do i contact you if i need more help

zepdrix (zepdrix):

Be sure to press "Close Question" when you feel it's be sufficiently answered. Create new questions in new threads. Just type @zepdrix somewhere in your thread and it will ping me to get my attention :o

OpenStudy (anonymous):

Haha will do thanks again!

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