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OpenStudy (anonymous):
Solutions and Mixtures Stoichiometry
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OpenStudy (anonymous):
How many grams of aluminum hydroxide are required to neutralize a 275mL spill of 3.0 M HNO3?
OpenStudy (anonymous):
This is the equation: \[3HNO _{3}+ 1Al(OH)_{3} \rightarrow 1Al(NO _{3})_{3}+ 3 H _{2}O\]
OpenStudy (preetha):
moles of HNO3 = 3.0 x 275ml /1000(ml/L) moles of Al(OH3) needed = 3 x moles of HNO3 Convert moles of Al(OH)3 to g
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