integrate (x)(cos^3 x) dx
do you know the reduction formula for \[\int \cos^n x \,\mathrm dx\]
reduction?? nope...
first simplify cos^3 x in terms of cosine of 3x and x and then integrate by parts
i don't think here u should use reduction formula
its \[\cos ^3 x\] .. where did u get 3x and x @matricked
use cos3x =4 cos^3 (x) - 3cos x
why not? it solves the problem too, but the solution may not be attractive to @bii17
i mean use cos^3 (x) =1/4 *(cos3x +3cosx)
oh okay.. then what will happen next ? @matricked
and then use by parts
\[1/4 [x(\cos 3x + 3\cos x)]dx\] is this correct? @matricked
yup
so there will be u and du den dv and v... i used Dv as cos 3x dx the V will be 1/3 sin 3x ???
for both integration of 1/4 *xcos3x take x as the first function
i get it.. thanks a lot :) @matricked
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