Question

evaluate (a^4)^3
when a = (2r3)^1r6
Ill rewrite it neater

Answer 1

\[\huge(a ^{4})^{3} \]

Answer 2

\[ \huge a= (\frac{ 2 }{ 3 })^{\frac{ 1 }{ 6 }}\]

Answer 3

evaluate

Answer 4

i just sub a equal whatever in a^12 but i can never get it right

Answer 5

(a^4)^3 = a^(4*3)

(a^4)^3 = a^(12)

So if you want to find (a^4)^3, then you can find a^(12) instead since they are the same

Answer 6

\[ \Large a= (\frac{ 2 }{ 3 })^{\frac{ 1 }{ 6 }}\]

\[ \Large a^{12}\]

\[ \Large \left((\frac{ 2 }{ 3 })^{\frac{ 1 }{ 6 }}\right)^{12}\]

\[ \Large (\frac{ 2 }{ 3 })^{\frac{ 1 }{ 6 } * 12}\]

\[ \Large (\frac{ 2 }{ 3 })^{\frac{ 12 }{ 6 }}\]

\[ \Large (\frac{ 2 }{ 3 })^{2}\]

I'll let you finish

Answer 7

so the final answer is 4r9?

Answer 8

wow thanks so much anyways

Answer 9

you mean 4/9 right?

Answer 10

not sure how/where the r comes into play

Answer 11

btw \[\Large \frac{4}{9} = 4/9\]

Answer 12

oh lol in my calc to write something over something its something r something :P

Answer 13

oh interesting, never seen or heard of that before

Answer 14

actaully some question written in australia are written 8r9 which means 8/9

Answer 15

i gotcha, that makes more sense now

Answer 16

never ever seen that notation before