How can I find the two missing side-lengths of a right triangle if I just know one side-length and one angle measure, not counting the ninety degree angle?
I know that you use sin/cos/tan, but I would like a more elaborate explanaton
say we have this triangle with this given known angle |dw:1359721209010:dw|
and say we also know that the opposite leg is 5 units and the hypotenuse is unknown (so it's x units long at this point) |dw:1359721303048:dw|
Ok I'm following
we can then use the sine function sin(angle) = opposite/hypotenuse sin(30) = 5/x now solve for x sin(30) = 5/x 0.5 = 5/x ... use a unit circle or a calculator to find sin(30) = 0.5 0.5*x = 5 x = 5/0.5 x = 10 So if we know that the opposite leg of the 30 degree angle is 5 units, then we can figure out the hypotenuse of the right triangle to be 10 units long
|dw:1359721421226:dw|
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