Question

how to differentiate z=(1-2v+v^4)^-3/2

Answer 1

you should use chain rule

Answer 2

dz/dv=-3/2(1-2v+v^4)^(-3/2-1) * (-2+4v^3)

Answer 3

oh? thanks for the hint :)

Answer 4

like this
let u = 1 - 2v + v^4
then
\[\frac{ dz }{ du } u ^{\frac{ 3 }{ -2 }}*\frac{ du }{ dv }\]

Answer 5

like this

Answer 6

welcome..

Answer 7

i come up with z'=3(1-2v^3)/square rt. of (1-2v+v4)^5 :)

Answer 8

ur correct @doodlellatot

Answer 9

thanks helping me :)

Answer 10

go to calc101.com you will love it, it has working and everything