Question

will give medal to best answer!
The given measurements may or may not determine a triangle. If not, then state that no triangle is formed. If a triangle is formed, then use the Law of Sines to solve the triangle, if it is possible, or state that the Law of Sines cannot be used.

C = 38°, a = 19, c = 10

Answer 1

Did you try simply using Law of Sines to figure it out?

Answer 2

yes but i didnt understand

Answer 3

What did you come up with?

Answer 4

i got sin A = 67 but that isnt in my answer choices
No triangle is formed.

A = 58.6°, B = 83.4°, b ≈ 15.6

A = 83.4°, B = 58.6°, b ≈ 15.6

The triangle cannot be solved with the Law of Sines.

Answer 5

I don't understand how you got that. Please show me the steps you took to get A = 67

Answer 6

i used c/ sin c = a/ sin a
10/sin 37 = 19/sin a
and then i divided 19 sin 38 over sin 10 and i got 67.36

Answer 7

where did you get the 37 from?

Answer 8

I meant 38, i used 38 in my claculations and still got 67

Answer 9

calculations

Answer 10

Are you in degree mode or radian mode?

Answer 11

i dont know i just typed it in and got 67, cant you check it?

Answer 12

You must make sure you're in degree mode. That's very important.

Answer 13

But either way it goes, you're not doing it correctly.

Answer 14

oh really, i hadnt noticed that im doing it wrong. I need help thats why im on here obviously

Answer 15

\[\sin A = \frac{19\sin(38^{\circ})}{10}
\\\sin A =
\]

Answer 16

Compute the right hand side again and let me know what you get. Make sure you're in degree mode.

Answer 17

1.169756803

Answer 18

Okay now

\[\sin A = 1.169756803\]

So how do we find A?

Answer 19

a is 19, sin A is 1.16, what do you mean find A?

Answer 20

A is an angle. Find it

Answer 21

A is an Angle like theta

Answer 22

I'm not talking about a = 19. That's a side length

Answer 23

\[\sin (A^{\circ}) = 1.169756803\]

I'm talking about Angle A. Find that.

Answer 24

how?

Answer 25

You take the inverse sine of both sides to get:

\[\sin^{-1}(A^{\circ}) = \sin^{-1}({1.169756803})
\\A^{\circ} = \sin^{-1}({1.169756803})
\]

Answer 26

So compute \[\sin^{-1}({1.169756803})\]

Answer 27

Let me know what you get.

Answer 28

it says error

Answer 29

Exactly.

Answer 30

That's what it should say because no such angle exists.

Answer 31

And if the angle doesn't exist, then the triangle can't possibly exist.

Answer 32

\[-1< \sin(\theta) < 1\] means that the value of sine can only be between - or + one. So there's no such thing as \(\sin(\theta) = 1.17\)