Question

If the radius of a sphere is measured as 7 m with an error of 0.02 m, then find the
approximate error in calculating its volume.

Answer 1

@Yolo? @yololol

Answer 2

Why would I help you?

Answer 3

The answer is 6

Answer 4

you both look so sweet sid by side :) GOD Bless you...

Answer 5

Bye...

Answer 6

Thanks @chad

Answer 7

http://media.tumblr.com/tumblr_mdyb2b8jJu1rp7g3w.gif

Answer 8

is that you @becca ?

Answer 9

It's not me in the Gif, no.

Answer 10

lol

Answer 11

The approximate error would actually be 12 cubic meters.

~~~~~~~

Here's the formula for finding the volume of a sphere:

\[\frac{ 4 }{ 3 }\pi r^{3}\]

That's "four-thirds, times pi, times the radius CUBED."
(Not squared, even though the little 3 looks like a 2.)

~~~~~~~~~~~~~~

If we assume that the radius of the sphere is 7,
then the volume would be 1432.44 cubic meters.

But since the error is 0.02,
the ACTUAL radius of the sphere could be 7.02, or 6.98.

If we assume that the radius is 7.02,
then the volume would be 1444.76 cubic meters.

And if we assume that the radius is 6.98,
then the volume would be 1420.20 cubic meters.

~~~~~~~~~~~~~

The difference between 1444.76 and 1432.44 is 12.32.

And the difference between 1432.44 and 1420.20 is 12.24.

So you see,
the error is about 12.00 cubic meters, if we round it.

Answer 12

Damn you just wasted all your time writing that lol

Answer 13

Better than wasting my time on giving someone a wrong answer. Right?

Answer 14

@rebeccaskell94

Answer 15

He didnt really want an answer lol he was just trying to troll me and Becca

Answer 16

No...

Answer 17

@JamesJ

Answer 18

@goformit100

"No"?

Answer 19

Depending on whether I choose to multiply pi with 1.33,
or to multiply pi with 1.33333,
my spherical volume could be off by anywhere from 3 to 5 meters.

But in the end, the error is still about 12 cubic meters.