Please Help! I drew a picture already!

From a boat on the lake, the angle of elevation to the top of a cliff is 18°41'. If the base of the cliff is 991 feet from the boat, how high is the cliff (to the nearest foot)?

Question

Please Help! I drew a picture already!

From a boat on the lake, the angle of elevation to the top of a cliff is 18°41'. If the base of the cliff is 991 feet from the boat, how high is the cliff (to the nearest foot)?

anonymous · Answer

|dw:1359744334016:dw|

anonymous · Answer

$$\frac{cliff}{991}=\tan(18.68)$$
$$cliff =991\times \tan(18.68)$$

anonymous · Answer

so the cliff is 335.05 ft tall?

anonymous · Answer

let me check

anonymous · Answer

looks good to me

phi · Answer

try this video if you want more info on these kinds of problems http://www.khanacademy.org/math/trigonometry/basic-trigonometry/basic_trig_ratios/v/basic-trigonometry

anonymous · Answer

round the the nearest foot. it is 335 feet