find the future value of the ordinary annuity. Interest is compounded annually. r = $5000, i = 0.08 n = 10
\[5000(1.08)^{10}\]and a calculator
i came up with 14.48 it doesnt seem right
10794.62
oh.. r is $1000 not $5000
1000(1.08)^10=2158.92 right?
future.. do you add that to $1000?
@satellite73 am i close?
this is what i get http://www.wolframalpha.com/input/?i=5000%281.08%29^%2810%29
oh if it is $1000 then the answer is different
my problem changed cuz my answer was wrong...
what is the problem now?
interes rate changed to 0.09 i entered it into that site but the answer it gave me was wrong.
the interest rate is 0.09, what is the starting amount?
oh wait.. n is 20 lol hold on no it still showeed wrong.. r is $5000 i is 0.09 n is 20
ok lets do that one
my notes is showing that it hast to be divided by the interest
you lost me if you are compounding more than once a year you have to divide the interest rate by the number of compounding periods per year
255,800.60 was the correct answer
you need to know several things 1) the initial amount 2) the interest rate 3) the number of years 4) the number of compounding periods per year
my notes are showing r=[(1+i)^n-1/i]
we need all 4 numbers
what do all those variables represent?
r is annual interest i is interest rate per perod n is # of compounding periods
and it is \[r=(1+i)^{\frac{n-1}{i}}\] ?
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