Ask your own question, for FREE!
Mathematics 13 Online
OpenStudy (anonymous):

Please help :) U={3,5,7,9,11,13,15} A={3,5,7,9} B={7,9,11,13} C={3,11,15} a U c' ??

jimthompson5910 (jim_thompson5910):

first you need to find C' how do we do this?

OpenStudy (anonymous):

That seems to be where I am stuck, I know that I am looking for the compliment of C... correct?

jimthompson5910 (jim_thompson5910):

exactly, basically the set of things that are in U, but NOT in C

OpenStudy (anonymous):

Right, Ok so I have done that so far and I came up with {5,7,9,15} But I dont think that that is the completed answer....

jimthompson5910 (jim_thompson5910):

15 is in C, so how can it be in C' ?

OpenStudy (anonymous):

Oh I am sorry I ment to type 13

jimthompson5910 (jim_thompson5910):

good, C ' = {5,7,9,13}

jimthompson5910 (jim_thompson5910):

Now simply combine these numbers in C ' with the numbers in A A U C ' = {3,5,7,9} U {5,7,9,13} A U C ' = {3,5,7,9, 5,7,9,13} A U C ' = {3,5,7,9,13} .. remember to toss out duplicates and sort

OpenStudy (anonymous):

Ok but there is still another step correct?

jimthompson5910 (jim_thompson5910):

no that's the last step you basically "glue" the two sets A and C' together, sort and toss out duplicates

OpenStudy (anonymous):

I see!! Thanks so very much! You were so clear in explaining!!

jimthompson5910 (jim_thompson5910):

you're welcome

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!