Question

How many different ways are there to choose 2 of 4 different colors?

Answer 1

If you could explain as well, that would be great! :D

Answer 2

For your first pick, you can pick any of 4 colors, so that is going to be "4 times something" so far.

That leaves 3 colors of which you can pick any of the three. So, you have "4 times 3" so far.

Now, you in effect have "double-counted" because the order doesn't matter. So, you have "4 times 3 divided by 2" for your answer.

This is 4C2 which is 4!/(2! times 2!)

Answer 3

The answer is 6?

Answer 4

btw, "!" notation, the exclamation mark, is "factorial", which is a number times every successive integer under it until you get to 1.

Yes, the answer is 6.

Answer 5

The answer is 6 as long as it doesn't matter which of the 2 colors was chosen first. Then the answer would be 12.

Answer 6

Okay I see now! Thank you so much. You have helped a ton! :D

Answer 7

Good luck to you in all of your studies and thx for the recognition! @HorseCrazyGirlForever

And you're welcome!

Answer 8

A good way to visualize that it is 6 and that there is no order to the picking is to imagine grabbing 2 at the same time blindly out of a bag.

Answer 9

Sounded funny. Visualizing blindly.