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Mathematics 13 Online
OpenStudy (anonymous):

why do the lengths of 3 rectangles with measurements of .5"x.75", 1"x1.5" and 2"x3" form a geometric sequence? how do I write a geometric sequence for these lengths and a recursive or explicit formula for this sequence?

OpenStudy (anonymous):

here the rato of their lengths is constant hence the lengths for a geometric sequence)

OpenStudy (anonymous):

.5/1=.5 and 1/2 =.5 .75/1.5 =.5 also 1.5/3=.5

OpenStudy (anonymous):

So these lengths do make up a geometric sequence? How would I write that sequence?

OpenStudy (anonymous):

for gemetric sequence a,ar,ar^2,ar^3...... the nth term in the sequence is written as a_n=a_1*r^(n-1) a_n -->> nth term a_1--> first term r --> constant ratio

OpenStudy (anonymous):

n= number of terms

OpenStudy (anonymous):

do I have 6 terms

OpenStudy (anonymous):

here u have two geometric sequence one for length and the other for breadth

OpenStudy (anonymous):

is r=.5

OpenStudy (anonymous):

for length a_1 = .75 ,n =3 and r=0.5 for breadth a_1=0.5,n=3,r=0.5

OpenStudy (anonymous):

do i write a recursive or explicit

OpenStudy (anonymous):

to write a geometri sequence do I just list the lenghts:.5,1,2 and then do one for the widths:.75, 1.5.3

OpenStudy (anonymous):

use a_n=a_1*r^(n-1) a_n -->> nth term a_1--> first term r --> constant ratio ,n= number of terms

OpenStudy (anonymous):

a sub 3=.75(.5)^(n-1) and a sub 3=.5(.5)^(n-1) Are these correct and are these recursive or explicit formulas?

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