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Mathematics 10 Online
OpenStudy (anonymous):

what does in the standard form of a polynomial means ? explain

OpenStudy (anonymous):

If you googled it, you may find the answer. The answer I believe is that the standard form of a polynomial means the terms are arranged from highest to lowest. It makes sense that many questions with polynomials are grouped together. An example would be \[x^{3}+x^{2} - 1\]

OpenStudy (unklerhaukus):

\[\text{The standard form of an \(n\)-th order polynomial}\] \[a_1x^n+a_2x^{n-1}+a_{3}x^{n-2}+\dots+a_{n-1}x^2+a_{n}x+a_{n+1}\] where the \(a_1...a_n\) terms are the co-efficients \(a_1\) is nonzero (or else it wolden't be \(n\)-th order) and \(a_{n+1}\) is the constant term. Note that there can be a most \(n+1\) terms Also note that the powers of \(x\) are in descending order (left to right) There will be less terms if any of \(a_{2}\dots a_{n+1}\) are equal to zero

OpenStudy (unklerhaukus):

for example a particular 4rd order polynomial might be \[x^4+4+x+6x^3\] to convert this to standard form we need to arrange the terms in decreasing order of the powers of \(x\). (it might help to show the powers of \(x\) more explicitly ) \[x^4+4x^0+x^1+6x^3\] now rearranging the terms \[x^4+6x^3+x^1+4x^0\] we arrive at \[x^4+6x^3+x+4\] This is in standard from the coefficient of \(x^4\) is \(1\) the coefficient of \(x^3\) is \(6\) the coefficient of \(x^2\) is \(0\) the coefficient of \(x\) is \(1\) the constant term is \(4\)

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