*** I will give you a medal if you help/answer *** Simplify the sum. State any restrictions on the variables. (x-2)/(x+3) + (10x)/(x^2-9)
@tkhunny
It should be realatively obvious after you factor the right-side denominator.
do I switch it to multiplication and the recep after i factor it
?? Y ou first look at it and decide what will make the denominator zero. This will be the restrictions. After that, just add like any other fractions.
i don't know how... okay i factored.. and i got (x+3)(x-3) and that cancels out the (x+3)'s .. now what do i do ?
I learn step by step... soo could you go through it with me?
Here's a plan. Never use he word "cancel" again, unless you are talking about your CableTV Service. \(\dfrac{x-2}{x+3} + \dfrac{10x}{x^{2} - 9} = \dfrac{x-2}{x+3} + \dfrac{10x}{(x+3)(x-3)}\)
okay.
You need to remember how to add fractions. Common denominator? \(\dfrac{x-2}{x+3} + \dfrac{10x}{x^{2} - 9} = \dfrac{x-2}{x+3} + \dfrac{10x}{(x+3)(x-3)}= \dfrac{x-2}{x+3}\cdot\dfrac{x-3}{x-3} + \dfrac{10x}{(x+3)(x-3)}\) That is required to look VERY familiar.
okayy now what ???
We have common denominator. What shall we do next? Who told you that you learn "step-by-step"? That's kind of silly. Thinking that prevents you from learning other ways. Think back a few years. How did you add \(\dfrac{1}{3} + \dfrac{5}{6}\)?
I don't remember.. I honestly don't which is why I got on here to get help because my teachers teach me a pelletty as way and it's something I just can't follow. I'm sorry :(
pelletty way *
what the heck.. it wont let me say s h i t t y
Good. If you start talking that way you have to stop talking to me. If you cannot add 1/3 and 5/6, you cannot do this problem. No offense intended, it's just the way it is.
cool. glad your going to help me.. isn't that what this site is for?
Show me that you can add 1/3 ad 5/6 and we can talk. Some of the help you need seems to be a little reality therapy. I am quite happy to help you. I am not happy to waste your time if you do not have the necessary prerequisites to advance through the material.
obviously @jim_thompson5910 i need you to help me .
Seriously, just add 1/3 and 5/6. It is not much to ask.
@jim_thompson5910
i don't know how !!!!
you already found that (x-2)/(x+3) + (10x)/(x^2-9) (x-2)/(x+3) + (10x)/((x+3)(x-3)) So the LCD is (x+3)(x-3)
you need that first fraction to have the same denominator in order to add the two fractions
how do we do this
okayy. you multiply everything by the LCD to cancel out the fractions.
well you can only use that trick when you have an equals sign
but we don't have that here, so we just have to add the fractions like normal
ohh okay.
what is the first denominator missing to get it equal to the LCD
the (x-3)
so you need to multiply top and bottom of the first fraction by (x-3)
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