*** I will give you a medal if you help/answer *** The speed of the current in a river is 6 mph. A ferry operator who works that part of the river is looking to buy a new boat for his business. Every day, his route takes him 22.5 miles against the current and back to his dock, and he needs to make this trip in a total of 9 hours. He has a boat in mind, but he can only test it on a lake where there is no current. How fast must the boat go on the lake in order for it to serve the ferry operator’s needs?
Take 22.5 miles divide by 9 hrs to find speed on water without current and add 6mph to the speed ?
is this for sure how you do it.. ??
i got 8.5
thats how I would do it. think of it this way, u add 6 mph to the boat and it cancels out the river current, so your remaining speed is the speed needed to cross the river 22.5 miles in 9 hrs
@jim_thompson5910
let x = speed of the boat in still water now let's find the distance equation for the boat when it goes against the current d = rt d = (x - 6)*t ... the speed gets slowed down against the current, so that's why it drops to x-6 22.5 = (x-6)*t now solve for t 22.5/(x-6) = t t = 22.5/(x-6) So it takes 22.5/(x-6) hours to go 22.5 miles upstream ------------------------------------------- Now let's find the equation when the boat goes with the current d = rt d = (x + 6)*t the speed gets faster with the current, so that's why it bumps up to x+6 22.5 = (x + 6)*t 22.5/(x + 6) = t t = 22.5/(x + 6) So it takes 22.5/(x+6) hours to go 22.5 miles downstream -------------------------------------------------------- You want the two times to add to 9 hours, so... 22.5/(x-6) + 22.5/(x + 6) = 9 solve this for x to get your answer
how do i solve for x ?
find a LCM to cancel out the equations ? or what ?
good, multiply everything by the LCD to clear out the fractions
the LCD is (x-6)(x+6)
so i would multiply everything by 135 ?
oh
no (x-6)(x+6)
im confused ?
so i take 22.5(x-6)(x+6)
start with the first fraction |dw:1359789162551:dw|
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