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Mathematics 7 Online
OpenStudy (anonymous):

i need help ..

hartnn (hartnn):

@Bugay♥ Hi :) \(\huge \color{red}{\text{Welcome to Open Study}}\ddot\smile\) Post a specific question, and we'll try our best to help you :)

OpenStudy (anonymous):

by the method of mathematical induction prove that the following are valid for all positive values of n. 1.) n^3+2n is divisible by 3 2.) 2+2^2+2^3+ . . . + 2^n = n^2(2n^2-1)

OpenStudy (anonymous):

thanks @hartnn ..

OpenStudy (dls):

Satisfy by k Satisfy by k+1

hartnn (hartnn):

welcome :) do you know general steps for proving an identity by mathematical induction ?

OpenStudy (anonymous):

basis of induction , induction hypothesis and proof of induction..

hartnn (hartnn):

First we prove the result for n= 1 so, put n=1 in n^3+2n and check whether the answer is divisible by 3 .

OpenStudy (anonymous):

3 is divisible by 3 then?

OpenStudy (anonymous):

??

OpenStudy (anonymous):

hartnn : i thought you will help me.. ???

hartnn (hartnn):

i am sorry, i keep on getting disconnected..

OpenStudy (anonymous):

oh its ok..

hartnn (hartnn):

well, next step is to assume the result true for n=k so, k^3+2k is divisible by 3---->(A)

hartnn (hartnn):

now, using (A), we need to prove the result for n=k+1 that is, prove (k+1)^3+2(k+1) is divisible by 3

hartnn (hartnn):

using the fact that k^3+2k is divisible by 3 can you do that ? try it...

OpenStudy (anonymous):

no i cant :(( can you do it for me?

OpenStudy (anonymous):

@Tushara : hello..

OpenStudy (anonymous):

@hartnn : its okey thank you so much..

OpenStudy (anonymous):

hey m doing the problem... ill help u out in a bit

OpenStudy (anonymous):

@Tushara : i wish you can help me with this..

OpenStudy (anonymous):

OpenStudy (anonymous):

does the second proof have any rule on n? like n>1?

OpenStudy (anonymous):

the second proof is not true for n=1

OpenStudy (anonymous):

no..

OpenStudy (anonymous):

well then u cant prove the second one.... its just not true

OpenStudy (anonymous):

are you sure??

OpenStudy (anonymous):

let me check the given..

OpenStudy (anonymous):

yeah m sure

OpenStudy (anonymous):

we have to put n=1 to n^2(2n^2-1) right?? and if it is equal to 1 .. the theorem is true for n=1

OpenStudy (anonymous):

2^n=n^2(2n^2-1) for n=1 which is not true

OpenStudy (anonymous):

its not true for n=2 either

OpenStudy (kira_yamato):

OpenStudy (anonymous):

oops im sorry the given was wrong.. it should be 2+2^2+2^3+ . . . + 2^n = 2^(n+1) - 2

OpenStudy (anonymous):

okay,... well its a very easy proof... prove true for n=1, assume true for n=k, then prove true for k+1

OpenStudy (anonymous):

it is now true for n=1 right?? then? what i am going to do?

OpenStudy (anonymous):

assume true for n=k

OpenStudy (anonymous):

@Kira_Yamato : still i thank you..

OpenStudy (anonymous):

now prove true for n=k+1

OpenStudy (anonymous):

then?? i find difficulty in proof of induction :((

OpenStudy (anonymous):

have u practiced any induction problems before? if u have some induction examples in ur math text book... please go thru them

OpenStudy (anonymous):

all u have to do is this: prove that 2^(n+1)-2+2^(n+1)=2(n+2)-2

OpenStudy (anonymous):

my teacher dont taught mathematical induction to us.. i havent encounter it before..

OpenStudy (anonymous):

if u cant prove the above equation^ den its best for u to not study ahead and wait for ur teacher to teach u... just see if u can prove the above

OpenStudy (anonymous):

2^(n+1)-2+2^(n+1)=2^(n+2)-2 sorry i typed it up wrong before

OpenStudy (anonymous):

what should i prove? if it is equal?

OpenStudy (anonymous):

yes its equal... dats all u have to do for that question

OpenStudy (anonymous):

oh okey.. thanks..

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