Use function notation to write the equation of the line
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OpenStudy (anonymous):
OpenStudy (anonymous):
Hi i am doing question 2
OpenStudy (anonymous):
and i got f(x)=-1x + 0
OpenStudy (anonymous):
no
OpenStudy (anonymous):
No O:
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OpenStudy (anonymous):
is it f(x)=-0.5 + 0
OpenStudy (anonymous):
as the line passes through the origin so you have one point (0,0) and other point (2,6)
now the slope from these points is
6/2 = 3
so the equation is
f(x) = 3x+0
OpenStudy (anonymous):
Ok where break it down
OpenStudy (anonymous):
so the Y- intercept witch is b is 0 right?
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
Ok then whats the slope
OpenStudy (anonymous):
its 3 as i told you
OpenStudy (anonymous):
and how you got the slope
OpenStudy (anonymous):
slope = m =(y2 - y1)/(x2 - x1)
OpenStudy (anonymous):
how you got 2,6
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OpenStudy (anonymous):
from the graph
OpenStudy (anonymous):
But the points on the graph where -6 and 6 it was dotted
OpenStudy (anonymous):
you are talking about 1 or 2
OpenStudy (anonymous):
question number 2
OpenStudy (anonymous):
so if you look to the graph carefully what is the value of f(x) for x = 2
???
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OpenStudy (anonymous):
Huh you have to be little clearer
OpenStudy (anonymous):
you have to be alittle detailed and pacific
OpenStudy (anonymous):
and how you get 2
OpenStudy (anonymous):
on x-axis you have certain numbers right???
OpenStudy (anonymous):
Yeah the run go on
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OpenStudy (anonymous):
exactly
OpenStudy (anonymous):
What about the run
OpenStudy (anonymous):
now see the value of x = 2
OpenStudy (anonymous):
I dont i see a line and dots on certains parts of the line
OpenStudy (anonymous):
but i dont see how 2 is in it?
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I get it cause you used rise over run so you did the doted one on the top so you ran to 2 on the x axis then you went up 6 rise! so thats how you got 6/2
OpenStudy (anonymous):
Am i correct!
OpenStudy (anonymous):
exactlyyyyyyyyyyyyyyyyyyyyyyy
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OpenStudy (anonymous):
Hehehe i feel smart ^-^
OpenStudy (anonymous):
Hey can you stick with me on 1 more just incase so i can get a ahng of it
OpenStudy (anonymous):
hang*
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Yay thanks
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OpenStudy (anonymous):
OpenStudy (anonymous):
I am on question number 3
OpenStudy (anonymous):
find the slope first
OpenStudy (anonymous):
Yes it is 3
OpenStudy (kira_yamato):
Graph pass through (4,20) and (3,0)
slope = 20 (use (y1-y2)/(x1-x2))
So y = 20 (x - 3)
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OpenStudy (anonymous):
(3,0) (4,20)
OpenStudy (anonymous):
so i got right now f(x)=mx +3
OpenStudy (anonymous):
so how do i know witch dot i suppose to follow the top or the buttom one
OpenStudy (anonymous):
y-intercept is wrong @Need_Help_
OpenStudy (anonymous):
Is the y intercept is 20
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OpenStudy (anonymous):
going up
OpenStudy (anonymous):
its your free choice the slope will be same for any two points
OpenStudy (kira_yamato):
I think is 60 for y-int
OpenStudy (anonymous):
Ok so for now i am going to use the top so
OpenStudy (anonymous):
no its not 20
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OpenStudy (anonymous):
its -60
OpenStudy (anonymous):
so what is my y intercept so i can put it for b
OpenStudy (anonymous):
and how you guys got -60
OpenStudy (anonymous):
you have y = mx+b
put b = -60 in it you will get it
OpenStudy (anonymous):
But how you guys got -60
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OpenStudy (anonymous):
Did you ran to 4 then rise to 20
OpenStudy (anonymous):
ok from the start of this question you have to find the slope
slope = m = (20-0)/(4-3) = 20/1 = 20
now use point slope form to get the equation
OpenStudy (kira_yamato):
Oh yeah -60.
∆y/∆x = slope = 20
y - y0 = m (x - x0)
y - 0 = 20 (x - 3)
y = 20x - 60 (QED)
OpenStudy (anonymous):
ok give me a seocnd
OpenStudy (anonymous):
we ran from 3 to 4 on horizontal and ran from 0 to 20 on vertical
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OpenStudy (anonymous):
i got 20/1
OpenStudy (anonymous):
so thats right
OpenStudy (anonymous):
ok hold on
OpenStudy (anonymous):
so 20/1 is my slope right
OpenStudy (anonymous):
yes
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OpenStudy (anonymous):
So do i plug it in my f(x)=mx + b now?
OpenStudy (anonymous):
no
OpenStudy (anonymous):
Ok i did the first step what do i do next then?
OpenStudy (anonymous):
So what do i do with my 20/1
OpenStudy (anonymous):
use point slope form now
consider any point in this graph say (3,0)
now you have one point (3,0) and slope = m =20
y-y1 = m(x-x1)
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OpenStudy (anonymous):
this is point slope form
y-y1 = m(x-x1)
OpenStudy (anonymous):
where you get 3, 0
OpenStudy (anonymous):
from the graph i got this point
OpenStudy (anonymous):
is it the 3 on the graph that was dotted
OpenStudy (anonymous):
for x = 3 y = 0
so the point is
(3,0)
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OpenStudy (anonymous):
yes yes
OpenStudy (anonymous):
Ok so i got 20/1 and i got 3,0 so what do i do next
OpenStudy (anonymous):
thus (x1,y1) = (3,0)
m = 0
use this now
this is point slope form
y-y1 = m(x-x1)
OpenStudy (anonymous):
Uhh
OpenStudy (anonymous):
So you want me to plug 3,0 zero in right
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OpenStudy (anonymous):
y-0 = 20(x-3)
OpenStudy (anonymous):
got it??
OpenStudy (anonymous):
Ok gewtting it
OpenStudy (anonymous):
(x1,y1) = (3,0)
here
x1 =3 and y1 =0
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
so your answer is ?????
OpenStudy (anonymous):
y - 0 = 20x - 3
OpenStudy (anonymous):
no no
also multiply this 20 with -3
OpenStudy (anonymous):
oh the distrubtive property right right
OpenStudy (anonymous):
yes
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