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Mathematics 8 Online
OpenStudy (anonymous):

Use function notation to write the equation of the line

OpenStudy (anonymous):

OpenStudy (anonymous):

Hi i am doing question 2

OpenStudy (anonymous):

and i got f(x)=-1x + 0

OpenStudy (anonymous):

no

OpenStudy (anonymous):

No O:

OpenStudy (anonymous):

is it f(x)=-0.5 + 0

OpenStudy (anonymous):

as the line passes through the origin so you have one point (0,0) and other point (2,6) now the slope from these points is 6/2 = 3 so the equation is f(x) = 3x+0

OpenStudy (anonymous):

Ok where break it down

OpenStudy (anonymous):

so the Y- intercept witch is b is 0 right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Ok then whats the slope

OpenStudy (anonymous):

its 3 as i told you

OpenStudy (anonymous):

and how you got the slope

OpenStudy (anonymous):

slope = m =(y2 - y1)/(x2 - x1)

OpenStudy (anonymous):

how you got 2,6

OpenStudy (anonymous):

from the graph

OpenStudy (anonymous):

But the points on the graph where -6 and 6 it was dotted

OpenStudy (anonymous):

you are talking about 1 or 2

OpenStudy (anonymous):

question number 2

OpenStudy (anonymous):

so if you look to the graph carefully what is the value of f(x) for x = 2 ???

OpenStudy (anonymous):

Huh you have to be little clearer

OpenStudy (anonymous):

you have to be alittle detailed and pacific

OpenStudy (anonymous):

and how you get 2

OpenStudy (anonymous):

on x-axis you have certain numbers right???

OpenStudy (anonymous):

Yeah the run go on

OpenStudy (anonymous):

exactly

OpenStudy (anonymous):

What about the run

OpenStudy (anonymous):

now see the value of x = 2

OpenStudy (anonymous):

I dont i see a line and dots on certains parts of the line

OpenStudy (anonymous):

but i dont see how 2 is in it?

OpenStudy (anonymous):

OOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOOHHHHHHHHHHHHHHHH

OpenStudy (anonymous):

A light bulb just popped in meh head!

OpenStudy (anonymous):

I get it cause you used rise over run so you did the doted one on the top so you ran to 2 on the x axis then you went up 6 rise! so thats how you got 6/2

OpenStudy (anonymous):

Am i correct!

OpenStudy (anonymous):

exactlyyyyyyyyyyyyyyyyyyyyyyy

OpenStudy (anonymous):

Hehehe i feel smart ^-^

OpenStudy (anonymous):

Hey can you stick with me on 1 more just incase so i can get a ahng of it

OpenStudy (anonymous):

hang*

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

Yay thanks

OpenStudy (anonymous):

OpenStudy (anonymous):

I am on question number 3

OpenStudy (anonymous):

find the slope first

OpenStudy (anonymous):

Yes it is 3

OpenStudy (kira_yamato):

Graph pass through (4,20) and (3,0) slope = 20 (use (y1-y2)/(x1-x2)) So y = 20 (x - 3)

OpenStudy (anonymous):

(3,0) (4,20)

OpenStudy (anonymous):

so i got right now f(x)=mx +3

OpenStudy (anonymous):

so how do i know witch dot i suppose to follow the top or the buttom one

OpenStudy (anonymous):

y-intercept is wrong @Need_Help_

OpenStudy (anonymous):

Is the y intercept is 20

OpenStudy (anonymous):

going up

OpenStudy (anonymous):

its your free choice the slope will be same for any two points

OpenStudy (kira_yamato):

I think is 60 for y-int

OpenStudy (anonymous):

Ok so for now i am going to use the top so

OpenStudy (anonymous):

no its not 20

OpenStudy (anonymous):

its -60

OpenStudy (anonymous):

so what is my y intercept so i can put it for b

OpenStudy (anonymous):

and how you guys got -60

OpenStudy (anonymous):

you have y = mx+b put b = -60 in it you will get it

OpenStudy (anonymous):

But how you guys got -60

OpenStudy (anonymous):

Did you ran to 4 then rise to 20

OpenStudy (anonymous):

ok from the start of this question you have to find the slope slope = m = (20-0)/(4-3) = 20/1 = 20 now use point slope form to get the equation

OpenStudy (kira_yamato):

Oh yeah -60. ∆y/∆x = slope = 20 y - y0 = m (x - x0) y - 0 = 20 (x - 3) y = 20x - 60 (QED)

OpenStudy (anonymous):

ok give me a seocnd

OpenStudy (anonymous):

we ran from 3 to 4 on horizontal and ran from 0 to 20 on vertical

OpenStudy (anonymous):

i got 20/1

OpenStudy (anonymous):

so thats right

OpenStudy (anonymous):

ok hold on

OpenStudy (anonymous):

so 20/1 is my slope right

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

So do i plug it in my f(x)=mx + b now?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

Ok i did the first step what do i do next then?

OpenStudy (anonymous):

So what do i do with my 20/1

OpenStudy (anonymous):

use point slope form now consider any point in this graph say (3,0) now you have one point (3,0) and slope = m =20 y-y1 = m(x-x1)

OpenStudy (anonymous):

this is point slope form y-y1 = m(x-x1)

OpenStudy (anonymous):

where you get 3, 0

OpenStudy (anonymous):

from the graph i got this point

OpenStudy (anonymous):

is it the 3 on the graph that was dotted

OpenStudy (anonymous):

for x = 3 y = 0 so the point is (3,0)

OpenStudy (anonymous):

yes yes

OpenStudy (anonymous):

Ok so i got 20/1 and i got 3,0 so what do i do next

OpenStudy (anonymous):

thus (x1,y1) = (3,0) m = 0 use this now this is point slope form y-y1 = m(x-x1)

OpenStudy (anonymous):

Uhh

OpenStudy (anonymous):

So you want me to plug 3,0 zero in right

OpenStudy (anonymous):

y-0 = 20(x-3)

OpenStudy (anonymous):

got it??

OpenStudy (anonymous):

Ok gewtting it

OpenStudy (anonymous):

(x1,y1) = (3,0) here x1 =3 and y1 =0

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

so your answer is ?????

OpenStudy (anonymous):

y - 0 = 20x - 3

OpenStudy (anonymous):

no no also multiply this 20 with -3

OpenStudy (anonymous):

oh the distrubtive property right right

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

y-0=20x - 60

OpenStudy (anonymous):

hmm thats right now now right it in simple form

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