Calculate the volume of the solid, bounded by surfaces: z=x^2+y^2; z= 4x^2+4y^2;z=4
first take 4 common frm 2nd eq then subtract both equation x n y will b canceled n z will be = to 4
Okay.Then?
then by comparin method find the value of x n put it in any of equ then y will automatically come
Okay. Let's say I got the value of x, y and z. How will I calculate the volume? I am a bit rusty on triple integrals.
hmm thts pity difficult :P
multiply all the values didnt u get it?
Well the process I saw online was very difficult and it required a lot more effort. Just multiplication won't help.
ohky m sorry i dnt knw more then that m student of 1st year so0o m sorry :(
It's alright aliza. Thanks for the insight.:)
ur welcome nw m going just pray 4 ma tomorrows NSTC test leaving t,cr
Sure and don't worry you will do well.
:) inshaallah
inshaallah.
\[\int\limits_{0}^{2\pi}\int\limits_{1}^{2}\int\limits_{0}^{4}1 dV\]
|dw:1359821229243:dw|
that would be the projection on the x-y plane?
Okay.
so now try elimination one of x/y and write it interms of z and the other var
i mean y=root(z-x**2)
|dw:1359821411153:dw| i hope u know how to find the area of the shaded part? i mean in 2-d? extend it to 3-d adding a dz
fine let's make a guess.............state ur options i m in no mood to solve it either
2pi,8pi,6pi and 35/4
dose are the options... what do u think wud be a good gess
consider two circles x**2 + y**2=4 and x**2+y**2=1 what would be the area b/n them?
radius:2 and 1
4pi-pi? 3pi?
so area=3
times 4 and we get 12pi
nope now it's gone 3d multiply it with 4 #height ok? now it's 12 pi now approximate it to be a cone now wat's the volume of a cone?
owwww i didnt think of that..
4/3 * 12 * pi =8*pi ?
1/3(pi)(r^2)(h)
now find the closest answer
8pi
noo sorry it's 1/3 * 12 *pi 4pi now wat's the closest?
idk deres 2pi and 6pi and 8pi... i gess 2pi then
yup cone obviously has a larger volume :P guess that's it @shubhanknigam
Thank you both of you, Tushara and Avinash. You were a big help. Guess I can sleep now.
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