Question

Instructions: Help please.
Given that log 4= 0.6021, log 9= 0.9542 and log 12= 1.0792, evaluate each logarithm.
Problem --> log 4.096

Answer 1

Hints:
\[\log_{} 4.096=\log_{} \frac{4096}{1000}=\log_{} 4096-\log_{} 1000\]
\[4096=4^{6}\]

Answer 2

im sorry , i dont get it . can you clarify ?

Answer 3

Knowing that 4096 = 4^6 and being given the value of log 4 you can work out log 4096 by using the rule of logs:
\[\log_{} a ^{b}=b \times \log_{} a\]
You should know the value of log 1000.

Answer 4

3 ?

Answer 5

Yes. The value of log 1000 = 3.
Knowing that 4096 = 4^6 and being given the value of log 4 you can work out log 4096 by using the rule of logs:
\[\log_{} 4^{6}=6\times \log_{} 4=you\ can\ calculate\]

Answer 6

my final answer would be 3.61, correct?

Answer 7

Good work! My result is log 4.096 = 3.6126

Answer 8

THANK YOU :DDD

Answer 9

You're welcome :)