Question

can someone show me how this function would be graphed? y = -x + x and there is a little 2 over the last x? please help

Answer 1

you mean like this: \(\large y=-x+x^2 \) ???

Answer 2

or this: \(\large y=-x+\frac{2}{x} \) ??

Answer 3

yes

Answer 4

the first one

Answer 5

ok... can you factor the right side for me: \(\large y=-x+x^2 \) ???

Answer 6

having it factored will tell us where the graph will cross the x-axis (the zeros)

Answer 7

maybe writing the equation this way is better: \(\large y=x^2-x \)
factor the right side....

Answer 8

i dont understand how to do the graph at all

Answer 9

i have been haveing a hard time with these i need someone to draw the graph and explain how to do it

Answer 10

that's ok... you're question was to help graph.. i'm trying to do that but you need to answer my question on factoring first.... all these preliminary stuff will help graph the parabola....

Answer 11

main thing when graphing is to find the x and y intercepts.... factoring the right side will help locate the x intercepts....

Answer 12

ok how do i find out what x and y means?

Answer 13

ok... you can factor \(\large y=x^2-x=x(x-1) \), agreed?

Answer 14

yes

Answer 15

so the equation can be written as: \(\large y=x(x-1) \)

so it's easy to see that when x=0, y=0
what about when x=1, y= ???

Answer 16

would it be 1

Answer 17

try again...
\(\large y=\color{red}x(\color{red}x-1) \)
when x=1: \(\large y=\color{red}1 (\color{red}1-1) \)

Answer 18

so it would be 0 then right?

Answer 19

correct....

Answer 20

we've just found the x-intercepts... meaning the graph will go through these two points