Question

2,4,8,16,24,36,64,...,...
Find the next 2 numbers in the series and write a function to model it.

Answer 1

i tried, its not a polynomial function...

Answer 2

its a geometric series...

Answer 3

Seems geometric to me, which would follow the general structure of
\[\Large a_n=a_1q^{n-1} \]

Answer 4

nopes, it isn't...

Answer 5

true, the 36

Answer 6

oh your right.. lol fooled two of us XD

Answer 7

well it shouldn't be too far away, seems just like it changes depending on the \[ q \]

Answer 8

as long as you can model it into a function, yes.

Answer 9

hatnn

Answer 10

are u viewing my question

Answer 11

hartnn

Answer 12

i also tried \(2^n \pm something\)
but no use...

Answer 13

\[\Large a_n=\begin{cases}2^{\frac{n+1}{2}}\left(\frac{n+1}{2}\right)&,n \text{ odd}\\n^2&,n \text{ even}\end{cases}\]

Answer 14

nice! but can't that be written in single line ?

Answer 15

the odd-terms is semi exponential, the even-terms is quadratic. i guess there's no way to write it as a single expression

Answer 16

what method did you use sirm3d?

Answer 17

does it start at n=0,1...?

Answer 18

odd-terms, even-terms. solve each sequence separately.

Answer 19

i tried to do it separately for odd and even terms...but could not figure it out for odd terms...so thanks!

Answer 20

yw

Answer 21

any paticular method to follow ?

Answer 22

i factor the 2's completely in the \odd-terms. the other factors form an arithmetic sequence.

Answer 23

good thought :)

Answer 24

2^(3/2)*3/2=4.2426 for n=3????

Answer 25

it's \((n+1)\) in the numerator, not \(n\)

Answer 26

OIC, great work :)