What is the sum of the arithmetic sequence 140, 136, 132…, if there are 35 terms? 2,520 2,590 2,660 2,930
what formula would i use here @Dr.V ?
Ok, a bit harder question. You must first find the 35th term to use the formula from the previous problem. The explicit definition for this arithmetic sequence is 140 -4(n-1). Substitute n = 35 to find the 35th term in the sequence, then use the formula for the sum of a finite arithmetic series.
Thanks!
My pleasure. Sequences and series are great stuff !
wait, what do i do after i get the -122? what would it be equivalent to?
where would i place it in the next formula?
How did you get -122?
i did 14-4(35-1)
or would it be 340?
Ooops! You should do 140-4(n-1). 140 is the first term in the sequence.
oh wow, haha, i didnt notice that
It is easy to make typos!
i got 4
Great! Now try subbing into the formula we used for the other problem. Type in your substitution.
I don´t think i can do it since the wording is different :/
The summation formula is \[\frac{ n(first term + last term) }{ 2}\]
what would go in the (n) field? would the 4 be the last term?
n=35?
n is the number of terms in the sum. You are correct--4 is the last term
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