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Mathematics 16 Online
OpenStudy (anonymous):

What is the sum of the arithmetic sequence 140, 136, 132…, if there are 35 terms? 2,520 2,590 2,660 2,930

OpenStudy (anonymous):

what formula would i use here @Dr.V ?

OpenStudy (anonymous):

Ok, a bit harder question. You must first find the 35th term to use the formula from the previous problem. The explicit definition for this arithmetic sequence is 140 -4(n-1). Substitute n = 35 to find the 35th term in the sequence, then use the formula for the sum of a finite arithmetic series.

OpenStudy (anonymous):

Thanks!

OpenStudy (anonymous):

My pleasure. Sequences and series are great stuff !

OpenStudy (anonymous):

wait, what do i do after i get the -122? what would it be equivalent to?

OpenStudy (anonymous):

where would i place it in the next formula?

OpenStudy (anonymous):

How did you get -122?

OpenStudy (anonymous):

i did 14-4(35-1)

OpenStudy (anonymous):

or would it be 340?

OpenStudy (anonymous):

Ooops! You should do 140-4(n-1). 140 is the first term in the sequence.

OpenStudy (anonymous):

oh wow, haha, i didnt notice that

OpenStudy (anonymous):

It is easy to make typos!

OpenStudy (anonymous):

i got 4

OpenStudy (anonymous):

Great! Now try subbing into the formula we used for the other problem. Type in your substitution.

OpenStudy (anonymous):

I don´t think i can do it since the wording is different :/

OpenStudy (anonymous):

The summation formula is \[\frac{ n(first term + last term) }{ 2}\]

OpenStudy (anonymous):

what would go in the (n) field? would the 4 be the last term?

OpenStudy (anonymous):

n=35?

OpenStudy (anonymous):

n is the number of terms in the sum. You are correct--4 is the last term

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