Question

In a quadrilateral ABCD, the diagonals bisect each other at point T.

Based on the given information which statement is presented first to show that side AB is equal to side BC?

Angle ADT is congruent to Angle ATB.

Angle ATB is congruent to Angle CTB.

Side BC is equal to the diagonal AC of the quadrilateral.

Side AB is equal to the diagonal DB of the quadrilateral.

Answer 1

@jim_thompson5910

Answer 2

only 27 more after this :/

Answer 3

@jim_thompson5910

Answer 4

what did you get

Answer 5

hmmm not sure

Answer 6

does it give you a picture

Answer 7

no

Answer 8

then it's missing info because it's implying that we're dealing with a rhombus, but we need to know if the diagonals are perpendicular or not

Answer 9

i believe they are always perpendicular

Answer 10

yeah in a rhombus they are, but we're not told that

Answer 11

it just says ABCD is a quadrilateral

Answer 12

http://openstudy.com/study#/updates/4fca5a3de4b0c6963ad45b77 would u agree?

Answer 13

@jim_thompson5910

Answer 14

what do u think

Answer 15

yeah I agree, but something is still missing

I know the answer, it just seems odd why they left off this crucial piece of info

Answer 16

these two angles must be congruent in order for AB = BC

Answer 17

because you can then use the SAS rule to say

triangle ATB = triangle CTB

then use CPCTC to say AB = BC

Answer 18

ok thx...one more?

Answer 19

The figure shows a pattern of a regular hexagon and equilateral triangles.



Which of the following describes the correct method to find the measure of angle y?

The exterior angle of the hexagon is the angle of the equilateral triangle. y = 60°.

The exterior angle of the hexagon is the interior angle of the equilateral triangle. y = 180° – 60°.

The exterior angle of the hexagon is the exterior angle of the equilateral triangle. y = 180° – 120°.

The interior angle of the equilateral triangle and y are supplementary angles. y = 90° - 60°.

Answer 20

ok last one