Question

log√(x)=√(logx)
Solve for x

Answer 1

x=1

Answer 2

How did you get that answer?

Answer 3

\[ \begin{array}{rcl}
\log(\sqrt{x}) &=& \sqrt{\log(x)} \\
\frac{1}{2} \log(x) &=& \sqrt{\log(x)} \\
\frac{1}{4} \log^2(x) &=& \log(x) \\
\frac{1}{4} \log^2(x) - \log(x) &=& 0 \\
\end{array}
\]
Now it's a quadratic equation... interesting.

Answer 4

Note that you have to be careful about things like absolute values in this case.

Answer 5

Thanks a million!