Look at quadrilateral LMJK in the circle shown below. Based on this figure which statement proves that the opposite angles of an inscribed quadrilateral are supplementary? Angle KJM is a, angle KLM is b, and a + b + angle JKL + angle LMJ = 360°. Angle KLM is a, angle KJM is b, and a + b + angle JKL + angle LMJ = 360°. a = 2 × angle KJM, b = 2 × angle KLM, and a + b = 360°. a = 2 × angle KLM, b = 2 × angle KJM, and a + b = 360°.
@mathstudent55
@jim_thompson5910
are you familiar with the inscribed angle theorem
im familiar with it
can you see how this applies?
well ik that the quad is inscribed
honestly i have no idea...i did well on every section of geometry except for proofs
im awful
so each point of the quadrilateral is on the circle
that's what it means to be inscribed
understood
we know that arc KJM and arc KLM form a complete circle
so arc KJM + arc KLM = 360
the value of 'a' is the measure of arc KLM and the value of b is the measure of arc KJM so arc KJM + arc KLM = 360 is really saying b + a = 360
now this is where the inscribed angle theorem kicks in angle KJM cuts off the arc KLM, so angle KJM is exactly half of angle KCM ie angle KJM is exactly half of the value 'a' so we can write this as KJM = (1/2)*a and solve for 'a' to get a = 2*KJM
so C
yes
thx lol
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