Question

Chameleons catch insects with their tongues, which they can rapidly extend to great lengths. In a typical strike, the chameleon's tongue accelerates at a remarkable 280 for 20 , then travels at constant speed for another 30 .

Answer 1

280 m/s for 20 s?

Answer 2

280 m/s2 for 20 ms

During this total time of 50ms , 1/20 of a second, how far does the tongue reach?

Answer 3

so you would have \[(280-0)/20 = 14 \] for the average initial speed. Then\[280*30=8400\] so 8400 + 14 *20

Answer 4

First we find v_1 which is a*t_1
a= 280m/s^2
t_1=0.02s
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Then we know it travels with an average speed of v_1/2=v_2 during it's acceleration period.
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We know it travels at v_1 for a period of t_2
t_2 = 0.03 s
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Total distance: s = v_2*t_1+v_1*t_2

Answer 5

Leaving us with the answer s = 0.224 m = 22.4 cm