Question

AC + BC could equal 15

Always
Never
Sometimes

Answer 1

Well one side is 9. This can get tricky since if A = 1, B = 1, and C = 9 you'll have 18. And you can't have a zero side or a negative side. That's impossible

Answer 2

\[\rm AC = 9\]Now apply the Pythagorean Theorem.\[9^2 + x^2 = 15^2\]Any solutions to the above?

Answer 3

Turns out they could never, because the only solution is \(12\) but \(9 + 12 = 21\)

Answer 4

Also thinking about how AC + BC > 15, we could never get AC + BC = 15.

Answer 5

oh I remember doing that PArth...

Answer 6

Erm?

Answer 7

the a^2+b^2 = c^2

Answer 8

Triangle Inequality Theorem: One side of a triangle is less than the sum of the other two.

Therefore, 15 < AC + BC which is equivalent to AC + BC > 15.

AC + BC could never be equal to 15. There would be no triangle.

@daustin15