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Chemistry 18 Online
OpenStudy (anonymous):

Consider the overall reaction: 2A + B > A2B Step #1: 2A > A2 (slow) Step #2: A2 + B > A2B (fast) What is the rate law for the overall reaction using the elementary steps above?

OpenStudy (aaronq):

rate law is dependent only on the slow step

OpenStudy (anonymous):

so it'll just be rate = k [A] ^2??? :)

OpenStudy (anonymous):

@aaronq :)

OpenStudy (aaronq):

yep, thats it

OpenStudy (anonymous):

oh. thanks so much. :)

OpenStudy (aaronq):

no problem (:

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