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Mathematics 17 Online
OpenStudy (anonymous):

Give the value of the maximum or minimum of the function f(x)=x^2-1.

OpenStudy (anonymous):

it will be parabola wih lowest point at x=0

OpenStudy (anonymous):

\[f(x)=x^2-1\] \[f'(x)=2x\] \[f''(x)=2\] At S.P's (Stationary Points) f'(x)=0 \[2x=0\] \[x=0\] To find the y coordinate/value, sub the x value back into the original equation. \[y=-1\] To determine whether that point is a maximum or minimum, check the second derivative of the function. If the second derivative is greater than zero, then it's a minimum, if it's less than zero, it's a maximum. \[f''(x)>0\] Therefore Maximum Turning Point at (0, -1)

OpenStudy (anonymous):

Thank You

OpenStudy (anonymous):

Wait it's a Minimum.

OpenStudy (anonymous):

@NathalieeM And the question asks for the value. You just need to say Minimum Turning Point at x=0.

OpenStudy (anonymous):

That's all you got to do.

OpenStudy (anonymous):

Oh okay , got it (:

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