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Show that the point P,Q and Rwith position vectors a - 3b + c, -2a +3b + 4c, -b+2c are collinear
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Vectors are colinear if they are multiples of eac other so let's take a look \[a-3b+c\]\[-2a+3b+4c\]\[-b+2c\] so see if you can multiply one of them by another constant and get them. Essentially look for a directional vector that can get you to each of the point from each of the others
I think P,Q,R is co-linear if, P-Q=t(R-Q) $$P-Q=(a-3b+c)-(-2a+3b+4c)=3(a-2b-c)$$ $$R-Q=(-b+2c)-(-2a+3b+4c)=2(a-2b-c)$$ It is clear that $$(P-Q)=\frac{3}{2}(R-Q)$$ so these points are colinear
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