Question

How many 4 person committes are possible from a group of 9 people if there are no restrictions?

Answer 1

\[C_{4}^{10}\]..by combination

Answer 2

ie.10!/4! (10-4)!=210..i guess so..

Answer 3

soorry it will be 9C4

Answer 4

this 9 choose 4 written as \[\left(\begin{matrix}9 \\ 4\end{matrix}\right)\] which is
\[9!/(4!(9-4))\] solve from there.

This comes from binomial theorem but this is the general multiplicative form of is
\[\left(\begin{matrix}n \\ k\end{matrix}\right)\] read as n choose k and the mulitplicative form is \[n!/(k!(n-k))\]

Answer 5

@azolotor ..do we have to take \[P_{4}^{9}\] too?

Answer 6

I do not believe so