Question

A man invests his savings in two accounts, one paying 6 percent and the other paying 10 percent simple interest per year. He puts twice as much in the lower-yielding account because it is less risky. His annual interest is 3916 dollars. How much did he invest at each rate?

Answer 1

6/100 X10/100

Answer 2

thats not right

Answer 3

did you get a specific euation to find the answer from your teacher?

Answer 4

no! thats all i got

Answer 5

This one is tricky.

I=prt
I = 3916
P is not known
R is either 6 percent or 10 percent
He put twice as much interest in the lower percent
T one year - annually, so 1

3916 = (0.06 * 2p * 1) + (0.10 * p *1)

Answer 6

I think that is how you would set it up.

Answer 7

yeah that didnt work but thank you though!

Answer 8

How do you know?

Answer 9

i plugged the answers in and they didnt work!

Answer 10

y

Answer 11

@zepdrix