Find antiderivative 5x-x^(1/2) How come on the -x side the answer is 2x^(3/2) / 3 ? Does the 3/2 get flipped when it goes to the bottom?
Because \[ \frac{1}{3/2} = \frac{2}{3} \]
I wish I knew its bad retricethough, I think its a monkey eagle or vietnam eagle
Ok james so I don't just take the exponent and add one to it then put it on the bottom I actually have to take the exponent over 1?
Remember that the antiderivative of \( x^n, n \neq 1 \) is \[ \frac{1}{n+1}x^{n+1} \ \ (+ C) \] In this case,y ou want the antiderivative of \( x^{1/2} \), hence n = 1/2. Using the rule just written down, we have n = 1/2 and thus the antiderivative is \[ \frac{1}{1+ 1/2} x^{1 + 1/2} = \frac{1}{3/2} x^{3/2} = \frac{2}{3} x^{3/2} \]
if I take x^2 for example, its an easy x^(3) / 3
Yes
thanks JamesJ!
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