a straight ramp rises at an angle of 25.5 degrees and has a base 30 ft long.how high is the ramp? round to the nearest foot.

Question

anonymous · Answer

Use soh cah toa

$$Sin(\theta)=\frac{l(o)}{l(h)}$$
$$\cos(\theta)=\frac{l(a)}{l(h)}$$

$$tan(\theta)=\frac{l(o)}{l(a)}$$

where l(o) is the length of the opposite side, l(a) is the length of the adjacent side, l(h) is the hypotenuse

anonymous · Answer

draw a picture first

|dw:1359933955601:dw|

anonymous · Answer

you have a theta , looking for hypotenuse and have an adjacent  side


what relates hypotenuse with adjacent?

cosine does!

$$cos(\theta)=\frac{l(a)}{l(h)}$$

solve to get l(h) by itself and plug in =]

anonymous · Answer

idk how to do that @Outkast3r09

anonymous · Answer

you don't know how to solve for l(h)?

anonymous · Answer

nope not very good at math

unklerhaukus · Answer

the hight of the ramp is the length of the side opposite to the angle , ie l(o)  |dw:1359939934317:dw|

anonymous · Answer

Hint i think tan is best one here

anonymous · Answer

@k.rajabhishek

anonymous · Answer

tan 25.5=x/30 

Solve for x. Use arctan on both sides.

unklerhaukus · Answer

use the tangent relation ; solve for $l(o)$ by multiplying both sides of the equation  by $l(a)$. then plug in    $l(a)=30 [\text{ft}]$, and $\theta=22.5°$

anonymous · Answer

11.54138670

anonymous · Answer

|dw:1359940156004:dw|