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4^2x+3=1
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\[\large 4^{2x}+3=1\] Is this it?
no \[4^{2x+3} = 1\]
Well, then, question... to what exponent to you raise numbers to that the value is 1?
this is exponential equations not requiring logarithms
It will not need logarithms, but intuitively, there is an exponent sch that in general, when you raise a number to it, the answer is 1.
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this is the work sheet im working on and it says the answer is -3/2 and i dont know how to get that answer
Yeah, this will lead you up to it, but first, again, what exponent turns numbers into 1 when the are raised to it?
0
Precisely. So now we are left with \[\large 4^{2x+3}=1\] But we know that \[\large 1 = 4^0\] So the question becomes \[\large 4^{2x+3}=4^0\] Can you do it from here?
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yes
thxs
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