Calculus 2 problem. Help please.

y=e^x, y=e^2x, x=ln2, x=0

Find the area enclosed by the curves. Show steps please.

Question

Calculus 2 problem. Help please.

y=e^x, y=e^2x, x=ln2, x=0

Find the area enclosed by the curves. Show steps please.

dumbcow · Answer

$$A = \int\limits_{0}^{\ln(2)} (e^{2x} - e^{x}) dx$$

anonymous · Answer

Right, but what is the actual area. That's where I am having trouble. thanks.

anonymous · Answer

The answer is supposed to be 1/2, but I am not getting that.

zepdrix · Answer

Were you able to get through the integration step?
Before plugging in the limits.

zepdrix · Answer

Were you able to get this? :)
$$\large \frac{1}{2}e^{2x}-e^x$$

anonymous · Answer

Yes, I got that part, but I did the algebra wrong, looking at it now. 
I got the answer now. I have a quick question, however. How do you know which function to use first in the integration process?

anonymous · Answer

And is there anyway to give more than one medal?

zepdrix · Answer

No, just give to cow c: hehe

zepdrix · Answer

You mean which one is being subtracted when you setup the integrand?

Or do you mean which limit you're subtracting when you evaluate the integral (plugging in).

anonymous · Answer

I guess both. I thought I was okay on the integral, but I am questioning myself on it now.

zepdrix · Answer

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