Question

prove
sec^2θ/over/sec^2θ-1=csc^2

Answer 1

it helps to start with
\[\sec^2(x)-1=\tan^2(x)\] giving you
\[\frac{\sec^2(x)}{\tan^2(x)}\]

Answer 2

then you have
\[\frac{\frac{1}{\cos^2(x)}}{\frac{\sin^2(x)}{\cos^2(x)}}=\frac{1}{\sin^2(x)}=\csc^2(x)\]