Question

1. 8y 7 ÷ 4y 5
2. (18x 5 + 6x 4 - 12x 3) ÷ 6x 2 helppppp???

Answer 1

\[\frac{x^n}{x^m}=x^{n-m}\]

Answer 2

huh ?

Answer 3

so first take care of the constants,

\[\frac{8}{4}=\]

Answer 4

2

Answer 5

then you have

\[\frac{y^7}{y^5}\]

since they have the same base you can use the above property

so

\[\frac{y^7}{y^5}=y^{7-5}\]

Answer 6

so combine your constant and your variables to get

\[2y^{7-5}=2y^2\]

Answer 7

\[ (18x ^{5}+6x ^{4}-12x ^{3})\div6x ^{2} \] is the q btw it didnt post the powers

Answer 8

the second equation you need to split everything up into their own fractions

Answer 9

same for the first one

Answer 10

I have no idea how to do this

Answer 11

so

\[\frac{18x^5+6x^4-12x^3}{6x^2}=\frac{18x^5}{6x^2}+\frac{6x^4}{6x^2}-\frac{12x^3}{6x^2}\]

Answer 12

then do what we did in the first one

Answer 13

Still have no idea lol

Answer 14

Thanks guys