How many grams of H2 are needed produced in 11.13 grams of of NH3
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OpenStudy (aaronq):
can you write an equation for the reaction and balance it?
OpenStudy (anonymous):
3H2+N2\[3H _{2}+N _{2}\rightarrow2NH _{3}\]
OpenStudy (anonymous):
ignore the first part
OpenStudy (aaronq):
okay good stuff, now covert the grams of NH3 to moles
OpenStudy (anonymous):
ok so find the molar mass?
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OpenStudy (aaronq):
well yeah, then find the moles
moles=mass/molar mass
OpenStudy (anonymous):
17.034
OpenStudy (anonymous):
.653
OpenStudy (aaronq):
okay so you have this
3H2+N2→2NH3
x 0.653
now, you have to use the coefficients to form a ratio between the 2 substances, since they're not in a one to one relationship.
aA + bB -> cC
moles of C/c = moles of A/a
OpenStudy (anonymous):
see i dont understand that
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OpenStudy (aaronq):
all you have to do is normalize each one by diving the amount of moles by it's respective coefficient
\[\frac{ moles of H _{2} }{ 3 }=\frac{ moles of NH _{3} }{ 2 }\]