Question

Express the complex number in trigonometric form.

6 - 6i

Answer 1

\[a-bi= A \cos q\] avec \[A=\sqrt{(a^{2}+b ^{2)}} \]
et \[q=\tan^{-1}(-b/a) \]

Answer 2

Je ne parle pas pas francais :)
...
Anyway,
Let's start with a+bi, instead...
@suivpasyonw
is quite correct with how to find the value of A.
But... for q, which I'll call the argument, it is a little trickier than that, it's safe to first take
\[\large r = \tan^{-1}\frac{|b|}{|a|}\]
And then, to find q, there are 4 cases... I'm going to use degrees here, okay?
If a and b are BOTH POSITIVE
q = r.
If a is NEGATIVE and b is POSITIVE
q = 180 - r
If a and b are BOTH NEGATIVE
q = 180 + r
If a is POSITIVE and b is NEGATIVE
q = 360-r

ca va?
XD

Answer 3

I am so sorry @terenzreignz. I speak english as a second language and just forgot to write my answer in english :-)

Answer 4

So the answer would be \[6\sqrt{2}(\cos7\pi/4+isin7\pi/4)\]

Answer 5

I wish @jazzie u got my answer!

Answer 6

Yay !! Thank you (:

Answer 7

Good on you :)

Answer 8

@suivpasyonw
There were only two French words, and you used mostly Maths symbols, I don't think there was really a need to apologise :D

Answer 9

:D

Answer 10

Good @jazzie