Could you show me the order of operation I can utilize to solve: 2x^2-6x/6x-5 divide x-3/6x-5

Question

anonymous · Answer

$$(2x ^{2}-6x)\div (6x-5) \div (x-3/6x-5)$$ is it this operation u want to solve @Unevie_Benie

anonymous · Answer

Yes

anonymous · Answer

I apologize, the 2x^2-6x is above 6x-5 (like a fraction)

anonymous · Answer

you can do it in the order above

anonymous · Answer

did you get it?

anonymous · Answer

I am not sure of what steps to take to solve.  I am looking at youtube videos now.

anonymous · Answer

what do you mean? Do you have a value for x? or do you want to find the zeros of this equation?

anonymous · Answer

Simplify to lowest terms

anonymous · Answer

Ah!!!!!!!!!!!!! it is simple! The operation you have is equivalent to: $$[(2x ^{2}-6x)\div(6x-5)] \times[(6x-5)\div (x-3)]$$. So you can simplify by (6x-5)
Your fraction is reduced to:$$(2x ^{2}-6x)\div (x-3)$$
and :$$2x ^{2}-6x $$ is equal to$$2x (x-3)$$
You can simplify by x-3 and the final result will be 
$$2x$$

anonymous · Answer

@Unevie_Benie I think you can manage now! :) right?

anonymous · Answer

Yes, I think I can.  I will write it again so I am familiar with the steps and know how to apply them - I sincerely appreciate this.  Thank you.