If $200 is invested at 6% annual interest compounded continuously, when will the investment be worth $300

Question

anonymous · Answer

$$A = P(1+r/n)^{nt}$$ This is the equation for compounding interest. So plug in all your values and computer for the time. Hint: you may need to use a logarithim

anonymous · Answer

A=pe^n

anonymous · Answer

that formula... but i don,t what will bu evaluated to that

anonymous · Answer

i don't where will the values be substituted

anonymous · Answer

i don't know........ where it will be substituted

anonymous · Answer

Sorry misread the question A = the total amount 300 P is the principal amount r is the rate of interest 0.06 and t is the time compounded $$A = Pe ^{rt}$$

anonymous · Answer

so you may end up with lnA = rtlnPe

kropot72 · Answer

The formula to use for continuously compounded interest is as follows:
 $$A=Pe ^{rt}$$
  where, P = principal amount (initial investment)
r = annual interest rate (as a decimal)
t = number of years
A = amount after time t
NOTE: The usual formula for periodically compounded interest is not applicable.