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Is this correct? Find the values of x where the tangent line to the curve y = x^3 - 9x^2 + 24x - 10 is horizontal. f'(x) = 3x^2 - 18x +24 f'(x) = 0 3x^2 - 18x + 24 = 0 3(x^2 - 6x + 8) = 0 3(x-2)(x-4) = 0 x=2 x=4 The values of x where the tangent line to curve are horizontal at x = 2 and x = 4.
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you nailed it, nice work
Thanks so much will be posting more.
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