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Mathematics 15 Online
OpenStudy (anonymous):

Is this correct? Let f(x,y) = 2x^2 + 2xy + 3y^2 - 16x - 18y +54 (a) Find f_x (x,y) 4x+2y-16 (b) Find f_y (x,y) 2x+6y-18 (c) Evaluate f_x (1,-2) 4(1)+2(-2)-16 = -16 (d) Evaluate f_y (1,2) 2(1)+6(2)-18=-4

jimthompson5910 (jim_thompson5910):

again, every answer is correct

jimthompson5910 (jim_thompson5910):

nice work

OpenStudy (anonymous):

ok great wasn't sure I did it right. I get confused on the removing the y's and x's when they are right next to each other. for example the 2xy that threw me for a loop.

jimthompson5910 (jim_thompson5910):

you would just think of 2x as the constant if you were deriving with respect to y

jimthompson5910 (jim_thompson5910):

or 2y as the constant if you were deriving with respect to x

OpenStudy (anonymous):

ok I think I got it, was curious cause the 2xy is like saying (2)(x)(y) so I guess you just remove the x because it would be 2x which the derivative would just be 2 so the only things left are (2)(y). Is that right?

OpenStudy (anonymous):

However, if it was 2x^2y it would be 4xy right?

jimthompson5910 (jim_thompson5910):

yeah you can think of 2xy as 2yx = (2y)*x derive that with respect to x to get (2y)*1= 2y the 2y is being treated as a constant

jimthompson5910 (jim_thompson5910):

what are you deriving 2x^2y with respect to?

OpenStudy (anonymous):

x

jimthompson5910 (jim_thompson5910):

yes you are correct d/dx[2x^2y] = 4xy

OpenStudy (anonymous):

ok sweet, dang man you are freaking smart. I wish I was that good.

jimthompson5910 (jim_thompson5910):

just keep practicing it and you'll get it and master it in no time

jimthompson5910 (jim_thompson5910):

and you seem like you know what you're doing here, which is great

OpenStudy (anonymous):

Hope so I have to make an A in this class.

jimthompson5910 (jim_thompson5910):

I'm sure you will

OpenStudy (anonymous):

Thanks. I fanned you and would love to ask you questions when I have more. Talk to you later.

OpenStudy (anonymous):

And thanks for everything.

jimthompson5910 (jim_thompson5910):

alright, have a nice night

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