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Mathematics 15 Online
OpenStudy (anonymous):

what is the probability that year selected at random is a leap year?

OpenStudy (shubhamsrg):

1 of every 4 consecutive years is a leap year.

OpenStudy (perl):

it depends how many years youre looking at

OpenStudy (shubhamsrg):

Indeed.

OpenStudy (anonymous):

so your ans is 1/4?

OpenStudy (perl):

the probability is .25 that a given year is leap

OpenStudy (perl):

shuba, can you help me with a problem?

OpenStudy (shubhamsrg):

Hmm?

OpenStudy (perl):

shub, here

OpenStudy (shubhamsrg):

You;re right, it depends on how many years you have in the sample space.

OpenStudy (perl):

this is like the question, what is the probability you pick saturday from the days of the week , which is 1/7

OpenStudy (anonymous):

its not given how many years are in sample space. btw i think the probability should be 1/2 as the year can be leap year or not.

OpenStudy (perl):

so here the sample space is { leap , not leap, not leap , not leap } these are equally likely possibilities , so 1/4

OpenStudy (perl):

well its like being asked, what is the probability a given day is saturday? it is 1/7

OpenStudy (perl):

ok here is a better sample space

OpenStudy (anonymous):

@perl why you consider that sample space contains only 4 year?

OpenStudy (perl):

{ leap year, year after leap year, 2 years after leap year, 3 years after leap year}

OpenStudy (shubhamsrg):

Your logic is flawed @himanshu31 say you have to find a no. from (1,2,3,4,5) which is a multiple of 2 , so you'd say is is (1/2) ? since a no. is always divisible by 2 or not ?

OpenStudy (perl):

these are the only possibilities, like { sat, sunday mon, tue, wed, thurs, fri, }

OpenStudy (perl):

there are only 4 possibilities a year can be, its either a leap year, or its 1 year ahead of leap year, 2 years ahead of leap year, 3 years ahead of leap year

OpenStudy (perl):

using this distinction let x = # of years ahead of leap year . then your years have only 4 possibilities . and these possibilities are equally likely

OpenStudy (shubhamsrg):

Okay since we going into depths, I'd like to point out that every year which is divisible by 4 is NOT a leap year

OpenStudy (anonymous):

@shubhamsrg yeah got it..but what should be the answer? @perl why are you considering only consecutive years?

OpenStudy (shubhamsrg):

I mean not all years divisible by 4 are leap.

OpenStudy (perl):

himan, it doenst have to be consecutive

OpenStudy (perl):

, but every year falls in some order between the last leap year and the next leap year

OpenStudy (anonymous):

@perl i am saying on basis of your sample space

OpenStudy (perl):

well , im trying to show its similiar to days of the week . but you dont have to put the days in order ,

OpenStudy (shubhamsrg):

There are 97 leap years in ever 400 leap years.

OpenStudy (shubhamsrg):

Thats the case we got to take,

OpenStudy (kropot72):

To be exact the sample space should be considered. The duration of a solar year is slightly less than 365.25 days. Therefore corrections ate needed from time to time such as omitting 3 leap days every 400 years.

OpenStudy (anonymous):

@perl then why only 4? you can have any number of years.

OpenStudy (perl):

himan, its like picking a day , sunday, then monday is 1 day after, tuesday is 2 days after, etc

OpenStudy (perl):

every year has 4 possibilities, its either leap , small leap, middle leap, big leap

OpenStudy (anonymous):

@perl now this explanation seems right.

OpenStudy (perl):

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