Question

Eeny, meeny, miny, moe

Answer 1

The numbers 1,2,…,17 are divided into 5 sets. One set has 5 elements, one set has 4 elements, two sets have 3 elements and the last set contains the 2 remaining elements. Two players each choose a number from 1 to 17 at random. what is the probability that they choose numbers from the same set

Answer 2

hello

Answer 3

here is one possibility for the five sets
{ 1,2,3,4,5} { 6,7,8,9} {10,11,12} {13,14,15} { 16, 17}

Answer 4

now what is the probability the two players choose from the same set

Answer 5

2(5/17)

Answer 6

one moment, brb

Answer 7

so we want the probability they choose from the same set,

Answer 8

there are 5 sets , but they are different sizes , so the probability of picking them will weigh differently

Answer 9

we could label the sets, A, B, C, D, E but they are not equally likely to be picked

Answer 10

You know you can do this more rapidly if you have a calculator that can calculate combinations.

Answer 11

5,4,3,3,2 is their weight

Answer 12

I could do it this way, the probability of picking A is 5/17
P(A) = 5/17
P(B)=4/17
P(C)=3/17
P(D)=3/17
P(E)= 2/17

Answer 13

AA means first guy picked from set A, 2nd guy picked from set A,

Answer 14

o P( picking from same set ) = P ( AA or BB or CC or DD or EE )=
P(AA) + P(BB) + P(CC) + P (DD) + P (EE)

Answer 15

so P( picking same same set) = (5/17)^2 + (4/17)^2 + (3/17)^2 + (3/17)^2 + (2/17)^2

Answer 16

I have one question, after one player picks up a number, thus the total no. of elements get reduced by 1 in the set ?

Answer 17

I dont think so, because it says pick a number from 1-17

Answer 18

Apparently not, there is no physical representation of numbers, just selecting them out of thin air, at random, by two people who may not have contact with each other.

Answer 19

each person picks a number 1-17, and i think we can assume independence

Answer 20

hmm, fair enough

Answer 21

do you agree?

Answer 22

Me ? Yes I do

Answer 23

This took me a while... I also naively assumed this was without replacement... MUST READ THOROUGHLY...

Answer 24

Hey @Jonask
I never would have assumed this was a serious question what with it being "Eeny, meeny, miny, moe" and all :D

Answer 25

@Jonask does that make sense ?

Answer 26

lol yes ofcos @shubhamsrg raised a fair question on replacement ,
and its correct

Answer 27

i mean the answer is correct

Answer 28

it is with replacement

Answer 29

You want to practice probability, try my question.

Answer 30

http://openstudy.com/study#/updates/510faccee4b09cf125bd2190

Answer 31

yes i really wanna practice this probability

Answer 32

did i get the right answer ?
is this multiple choice