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Mathematics 15 Online
OpenStudy (anonymous):

help with trig identities?

OpenStudy (anonymous):

(sin)(tan*cos-cot*cos)=1-2cos^2

OpenStudy (anonymous):

Using identities I think it should be converted to \[(\sin)(\frac{ \sin }{ \cos }\times \frac{ \cos }{ \cos }-\frac{ \cos }{ \sin }\times \frac{ \cos }{ \cos })=1-2\cos^2\]

OpenStudy (anonymous):

but i dont know what to do after that

OpenStudy (anonymous):

\[(\sin)(\frac{\sin}{\cos}\times \cos - \frac{\cos}{\sin}\times \cos)\]

OpenStudy (anonymous):

okay now?

OpenStudy (anonymous):

Would that be \[(\sin)(\frac{ \sin \cos }{ \cos^2 }-\frac{ \cos^2 }{ \sin \cos })\]

OpenStudy (anonymous):

\[\sin ( \sin-\frac{\cos^{2}}{\sin}\]

OpenStudy (anonymous):

okay?

OpenStudy (anonymous):

you got that from my answer? or is that what I should have simplified it to?

OpenStudy (anonymous):

u should have simplified.. cos and cos gets cancelled left with sin alone.

OpenStudy (anonymous):

numerator with the numerator and denominator with denominator always

OpenStudy (anonymous):

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