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A function f(x) is said to have a removable discontinuity at x=a if: 1. f is either not defined or not continuous at x=a. 2. f(a) could either be defined or redefined so that the new function IS continuous at x=a. Let f(x)=x−22x2+4x−16 Show that f(x) has a removable discontinuity at x=2 and determine what value for f(2) would make f(x) continuous at x=2. Must define f(2)=?
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Got it, it is 12. factor 2 first , then (x-2) then get the limit of f(2) by plugging 2 into the final function which is 2(x+4) and that will give you 12
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