The rational function has a y-intercept of What is the equation for this function?
I'm not really getting it :/ can u explain it please
horizontal asymptote is \(x=-3\) so the denominator is probably \(x+3\)
vertical asymptote is at \(y=5\) so it is something like \[y=\frac{5x}{x+3}\] but since it crosses the \(y\) axis at \((0,7)\) you have something like \[y=\frac{5x+7}{x+3}\]
no that was wrong!!
sorry. since \(0\) gets you 7 you can solve \[\frac{5x+b}{x+3}=7\]
ohh ok so this is the final answer o.O sorry a little confused
jeez i am an idiot, sorry let me try again
we know it looks like \[y=\frac{5x+b}{x+3}\] because of the asymptotes
ok
we know that if \(x=0\) we get \(y=7\) so solve \[\frac{b}{3}=7\] and get \(b=21\)
therefore it should be \[y=\frac{5x+21}{x+3}\]
ohh ok
damn i mean \[f(x)=\frac{5x+21}{x+3}\] http://www.wolframalpha.com/input/?i=%285x%2B21%29%2F%28x%2B3%29+domain+-9..9+
nice head on ;D thanks
yw
Thanks :D <3
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